Factors-12
From Homeworkwiki
Factorize :
(i) 8a 3 - 27b3
(ii) 2a7 - 128a
Solution :
(i) 8a3 - 27 b3
= (2a)3 - (3b)3
= (2a - 3b)(4a2 + 6ab + 9b2)
(ii) 2a7 - 128a
= 2a(a6 - 64)
= 2a[(a3)2 - (8)2]
= 2a[(a 3 + 8)(a3 - 8)]
= 2a(a3 + 23)(a3- 23)
= 2a(a + 2)(a2 - 2a + 4)(a - 2)(a2 + 2a + 4)
= 2a(a + 2 )(a - 2)(a2 - 2a + 4)(a2 + 2a + 4)
