Trigonometry-9

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An aircraft climbs at an angle of 30⁰ at a speed of 500 meters per second.

How long will it take to reach a height of 15000 meters?

Solution: Height ascended by the aircraft = BC = 15000 m.

Sin A = Sin 30⁰ = 15000 / AC

i.e. 1/2 = 15000 / AC

Therefore, AC = 2 X 15000 = 30,000 m

The aircraft travels 500 m in 1 second. Hence to travel, it takes

30,000 / 500 = 60 seconds